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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 19:15:11 IST
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If f(x) be a continuous function for all real values of x and satisfies;
x2 + {f(x)-2}x+2 *31/2 -3 -31/2.f(x)=0
 x R.Then find the value of f(31/2)
ANS:f(31/2)=2(1-31/2)
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16 May 2008 19:22:50 IST
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can u explain u r question further....?plz
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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16 May 2008 20:54:32 IST
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=\frac{2x-{x}^{2}%2B3-2\sqrt{3}}{x-\sqrt{3}}\;u\;can\;clearly\;see\;that\;u\;cannot\;sub\;x=\sqrt{3}\\but\;since\;f(x)\;is\;continous\;f(\sqrt{3})=\mathop{\lim}\limits_{{x} \to {\sqrt{3}}} f(x)\;now\;use\;L'hospital's\;rule\;f(\sqrt{3})=2(1-\sqrt{3})\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;.)
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16 May 2008 21:09:32 IST
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send the f(x) terms other side
(3^{1/2}-x)=x^2-2x%2B2(3)^{1/2}-3)
-2(x-3^{1/2})=-f(x)(x-3^{1/2}))
on simplification
=2-(x%2B3^{1/2}))
now substitute x value
f(x)=2(1-3^1/2)
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<SRIRAM.A> on high way of IIT
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