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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 May 2008 12:01:53 IST
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limit -(cot x - 1/x)
x tends to 0
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20 May 2008 12:07:30 IST
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Simplify it becomes
tan x - 1 / x^2
Am Not Sure But Then The Answer Should Be 0
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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20 May 2008 12:11:07 IST
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Not understanding please explain
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20 May 2008 12:13:16 IST
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But Is 0 Correct ?
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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20 May 2008 12:19:23 IST
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No , i dont know answer but please explain yaaaaaaaaaaar
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20 May 2008 12:24:26 IST
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yes the answer is 0
see it becomes cos x/sin x-1/x
on further solving we get
(cosx-1)/x while x tends to 0 and it is always =0
hope u got it....
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20 May 2008 12:25:45 IST
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Chill :)
See,
-(cot x - 1)/x
= 1 - cot x / x
= 1 - 1/tan x /x
= tan x - 1 / x tan x
Since X > 0
tan x = x
= tan x - 1 / x^2
Now If U Use McLaurin Series
tan x = 1 + x! / 1 + x^3 / 3! .....
there is no term of x^2
Hence Answer Should be 0
Alternately
d/dx (tan x) = sec^2 x
d/dx (sec^2 x) = 2 sec x sec x tan x
Thus by Using L'Hospital
= 2 sec^2 x tan x / 2 x
= sec ^2 x
= 0
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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20 May 2008 12:27:44 IST
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Sorry In the Last Part There Is Mistake :
Thus by Using L'Hospital
= 2 sec^2 x tan x / 2 x
= sec ^2 x
= 0
It Should Be
= 2 sec^2 x tan x / 2
= sec^2 x tan x
= 0
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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20 May 2008 19:15:59 IST
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= 
= 
= 
= 0
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
    
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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