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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 21:39:39 IST
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When a particle moves on a curved path,its acceleration can't be tangent to the path.Why?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 21:48:12 IST
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when a particle moves in a curved path , it has two accelerations - one is the centripetal acc. , directed invards . And the other is tangantial acc. , directed along the tangent to that point . So , the net acc. can be calculated by finding the resultant by IIgm law of vector addition . What u r saying does not make any sense
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 21:55:06 IST
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Hey kvn ! pls reply !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 22:11:42 IST
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dude it's acceleration has to b tangential,i cant get ur question!!!!
plz reply!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 22:13:01 IST
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when a particle moves in a curved path , it has two accelerations - one is the centripetal acc. , directed invards . And the other is tangantial acc. , directed along the tangent to that point . So , the net acc. can be calculated by finding the resultant by IIgm law of vector addition . What u r saying does not make any sense
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 22:34:02 IST
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first of all.. nuthin "oh no!" abt circular motion... second umang is completely right and therefore so is andy...  there are two accelerations- 1. tangential acc. 2. centripetal acc. if the radius of the circle changes then u might have radial accn also... but dont complicate things.. the resultant acc. is the vector sum of the two acc mentioned above.. one component is along the tangent... [as u can deduce from the name itself!!] reply and rate pls... thanx.
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***Time has made fools of us yet again...!*** |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 23:17:06 IST
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sorry dudes,didn't make my questions clear.In actual my doubt was that from "electricity".the complete question is:- "If a charged particle of charge q is in motion where there is an electric field,it is not necessary that particle must move along an electric field." GIVEN explanation is:- Because E at any pt. is tangent to the field line that passes through that point,it is indeed true that the force F=qE on the particle and hence the particle's accn.,are tangent to the field line.As when a particle moves in a curved path,its accn can't be tangent 2 the path.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2007 01:19:06 IST
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for net accleration to be tangential direction centripetal accleration should be 0 or mv2/r=0 for this either v=0 or m=0 or r= either of these three is not possible if body is in circular motion
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2007 16:46:32 IST
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Thats perfect rishikesh. The centripetal force is always along the radius of the curve and thus the centripetal acceleration. And the tangential acceleration of the body along with centripetal acceleration decides the resultant acceleration (using parallellogram law of vectors).
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The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2007 18:16:46 IST
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because of centripetal force
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