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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 May 2008 07:20:19 IST
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Consider interference between two sources of intensity I and 4I. Obtain intensity at a point where phase difference is <pi>/2.
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My teacher gave this formula : I = a12 +a22 + 2a1a2cos@ (i have no idea about derivation)
According to this, answer comes to 5I..but this is destructive interference!!
What's the correct formula to be used?
If possible, please tell how to derive it also..
Rates assured!
Thanks!!:-)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 May 2008 16:29:23 IST
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Please help!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 May 2008 18:40:48 IST
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formula to be used

so this give I=3I
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Do I NeEd A SiGnAtUrE To PrOvE MySeLF!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 01:20:35 IST
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so formula modifies to 
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 01:26:47 IST
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ur answer is correct but its not fully destructive interference where phase diff =pie
nor fully constructive
THE CASE HERE CORRESPONDS TO AVG VALUE OF I MAX AND I MIN
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 01:30:24 IST
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I MEAN THE INTENSITY INCREASES BECAUSE ITS NOT DESTRUCTIVE INTERFERENCE!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 16:36:51 IST
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Guys which is the correct formula ?The one given by eshaan or by divinexsoul?
And how is this formula derived?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 16:37:58 IST
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the formula given by divine is correct
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 16:58:18 IST
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Ok,could you tell me how its derived?
Thanks:-)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 17:10:17 IST
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go to http://www.goiit.com/chapters/tutorial/physics/superposition-3.htm
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 17:30:22 IST
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Thanks!:-)
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