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hary

me to getting 12.5

hary

c da shadow here forms da base of da right angled triangle n da tower forms da height of da right angled triangle

in da 1st case tan $\alpha$ =17.5/40.25

in da second tan $\alpha$ =x/28.75 (angle is same since it is da same situation)

by equating both da eq v get x=12.5

pi

answer-
1-b)7 7+6+5+4+3+2=27

2-b) 25%

let the total marks be x.so 1st score is 60/100x=0.6x
2nd score's 75/100x=0.75x

difference in score=0.75x-0.6x=0.15x
so % increase=0.15x/0.6x *100=25%

karansingh

For Q1,
a + (a+1) ......... + (a+6) = 27
6a + 21 = 27
a = 1.
So largest no = a + 6 = 7. (b)

For Q2,
improvement = 75 - 60 = 15.
But note that just as profit % is calculated on CP, improvemnt % upon previous score.
So improvemt % = 15 * 100 / 60 = 25 % (b)

For Q3,
due to similarity of conditions, triangles are similar.
or ... object height / shadow height = constant.
So 17.5 / 40.25 = ? / 28.75
or ? = 12 m.

Rate me if i am correct.

dream_iit

ans 1) check by options

2+3+4+5+6+7=27 (7 being the largest)

ans 2) let total marx = 100

first he scored 60 , then 75

so marx increased = 25....

25/100)*100 = 25%

nishant13940

ans ofthirdquestion is 12.5 meter.........

necrophilia666

first ans 7.

necrophilia666

second ans shud b 25%. if 60 refers 2 60%.

as for da flagstaff da ans is 12.5. one can simply equate the ratios given

cutie_divs91

1.) answer is 7
2.) answer is 25%
3.) answeer is 12.5m

rudra.panda

2+3+4+5+6+7=27
so 7 is the largest number.
OR

a+a+1+a+2+a+3+a+4+a+5=27
a=2 and a+5=7
rate if correct.

anay_pat

1. x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=27
6x+15= 27
x= 2
(x+5) = 2+5 = 7

2.Let total marks be x
Marks in 1st semester =60x/100
Marks in 2nd semester=75x/100
Imp. in marks =75x/100-60x/100 =15x/100
% imp of marks = {Imp / Original} *100 = (15x/100) / (60x/100) * 100
=25%

3.Due to similarity of conditions
Both the right angled triangles are similar
Shadow 1/ Shadow 2 = Height 1/ Height 2
40.25 / 28.75 = 17.5 / Height 2
Height 2 = 12.5 m

zeeshanp

da 1st answer is b....7

redsaredevils

1.a+a+1+a+2+a+3+a+4+a+5=27
=>a+5=7(Ans.)

2.Let total marks be x
Marks in 1st semester =60x/100
Marks in 2nd semester=75x/100
Imp. in marks =75x/100-60x/100 =75-60x/100=15x/100
% imp of marks = {Improvement / Original} *100 = (15x/100) / (60x/100) * 100
=25%

Everybody's ans is the same.

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