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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jun 2008 20:38:37 IST
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IN THE ARRANGEMENT A ROD OF MASS M IS HELD BT 2 SMOOTH WALLS ALWAYS PERPENDICULAR TO THE SURFACE OF THE WEDGE OF MASS m. ASSUME ALL AREAS FRICTIONLESS FIND THE ACC OF BOTH THE BLOCKS
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jun 2008 20:53:49 IST
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Just make both of them move by a small distance and double differentiate to get relation between their accelerations. Rest is simple.
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jun 2008 21:25:53 IST
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step1. identify constraint dirn for the 2 bodies in Q
step2. draw the dirn of motion along the dirn reqd.
step3.assume that the bodies r moving by x1 , x2 etc.
step4. based on the constraint, work out the reln btw the distances moved by the bodies.
step5.Based on this reln. express the relationship btw accln.
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altitude begets altitude. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2008 07:00:59 IST
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I DONT WANT THE RELATIONSHIP BETWEEN THE MASSEES I WANT THE ABSOLUTE ACCLERATION
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jun 2008 12:43:56 IST
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PLS SOLVE
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jun 2008 12:47:14 IST
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look...The components of velocity of the wedge in the direction of the Motion of the block are equal..hence we get a relation like the ratio of those two velociies is tan theta
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jun 2008 12:49:19 IST
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I mean You get a constraint equation
The velocity component of The block in the direction perpendicular to the wedge is equal to the velocity component of the wedge in the same direction..otherwise the block wud go inside the wedge :P
using tht you can proceed .. rate if found useful :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jun 2008 19:41:27 IST
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HOW MANY TIMES WILL I TELL THAT I WANT ABSOLUTE ACCLERATION NOT THE RELATION BETWEN THE MASSES
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jun 2008 07:19:45 IST
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PLS EXPERTS HELP
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jun 2008 07:37:31 IST
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ENOUGH IS ENOUGH I HV POSTED THIS SUM FROM PAST 5 DAYS AND I DONT EVEN GET A REPLY FROM A SINGLE EXPERT
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jun 2008 08:50:59 IST
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is there any wall which is touching the wedge??
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jun 2008 09:06:00 IST
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hey can u plz post da answers
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jun 2008 09:38:46 IST
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is @ the angle of inclination
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jun 2008 10:04:24 IST
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assumptions:
from ur dig it looks lik the wedge can move only downwards
variables:
let me call angle of inclination of wedge as @ ,its acc as a1(downwards)..let acc of the rod be a2(perpendicular to the wedge)..the normal force between them is N
method:
now it is direct tht the 2 acc are related as
a1=a2sec@-----(1)
now for rod:
Mgcos@-N=Ma2---(2)
for wedge:
mg + Ncos@ =ma1---(3)
solve
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jun 2008 16:37:33 IST
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