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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 12:39:36 IST
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A point P(  3,1) moves on a circle x 2+y 2=4 and after covering a quarter of the circle leaves it tangentially.The equation of a line along which the point moves after leaving the circle is: (A)y=  3x+4 (B)  3y=x+4 (C)  3y=x-4 (D)y=  3x-4
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 12:52:29 IST
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it is B , C actually i am getting [2 ] 3y = -x +- 4 in stead of sqroot(3)y = x +-4
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 13:46:57 IST
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it is (a)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 14:40:09 IST
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it is b,c for sure.
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SAARE JAHAAN SE ACHCHA;
GOIIT HAMARA!!!!!!!!!!!!!!!!!!!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 14:40:49 IST
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it is b,c for sure.
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SAARE JAHAAN SE ACHCHA;
GOIIT HAMARA!!!!!!!!!!!!!!!!!!!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 15:44:50 IST
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Let the center of the circle be O i.e. (0,0) and P moves quarter of the circle i.e. 90 degree to reach at point Q. Then OP and OQ will be perpendicular to each other. Let Q (h,k) then slope of OP = 1/  3 and slope of OQ =k/h so (1/  3) (k/h) =-1 or k= -  3h.......[1] since Q will be on the circle. so h^2+k^2 =4..........[2] from [1] and [2] : h=1 and k= -  3 or h= -1 and k=  3 so Q : (1,-  3) or (-1,  3) now eq. of tangent at Q : x-  3y=4 and -x+  3y=4
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 15:51:53 IST
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 15:53:17 IST
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sooorrry it is A,D 100 % sure
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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