}^{2} %2B {y}^{2}} = 2\sqrt{{(x%2B1)}^{2} %2B {y}^{2}})
squaring on both sides, we get
(x-1)^2 + y^2 = 4 [(x+1)^2 + y^2]
x^2 + y^2 - 2x + 1 = 4(x^2) + 4(y^2) + 8x + 4
3(x^2) + 3(y^2) + 10x + 3 = 0
x^2 + y^2 + (10/3)x + 1 = 0
comparing with standard form...
centre = (-5/3,0)
radius = rt[(5/3)^2 - 1] => rt[ 25/9 - 1] => rt(16/9] => 4/3 units...
Hope u got it...