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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2007 21:51:14 IST
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Calculate the kinetic energy of the electron when ultra violet radiation of frequency 1.6 * 1015/s strikes the surface of potassium metal .Threshold frequency of potassium is 5 * 1014 /s i want to know which principle is applicable and why?
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sikha
Success is how high you bounce when you hit bottom. |
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25 Mar 2007 21:59:43 IST
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can you post it in a better way..
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life is real ...the life is earnest..and grave is not its goal..
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25 Mar 2007 22:02:37 IST
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wats the ans
5h - plancks const.
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25 Mar 2007 22:05:49 IST
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1use Einstein's photoelectric equation, hf=hfo+KE 6.6x10-34x1.6x1015=6.6x10-34x5x1014+KE Now find the value of KE!!!! Here,f0 is called as threshold frequency!! If satisfied,rate me!!!
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25 Mar 2007 22:07:47 IST
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i used k.e = h (v - vo)
v = freq.
vo = threshold freq.
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I always like to walk in rain as no one can see me crying there :(
frnds are like diamonds , if u hit them , they don't break but they slip frm ur hands
-----It is better to be hated for what you are than to be loved for what you are not.----
*****wen love and skill work together--expect a masterpiece*****
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25 Mar 2007 22:22:20 IST
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but i dont think u would get 5h!!
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25 Mar 2007 22:25:04 IST
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sry then ans will cum 11h my mistake
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I always like to walk in rain as no one can see me crying there :(
frnds are like diamonds , if u hit them , they don't break but they slip frm ur hands
-----It is better to be hated for what you are than to be loved for what you are not.----
*****wen love and skill work together--expect a masterpiece*****
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25 Mar 2007 23:03:33 IST
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Problem) Calculate the kinetic energy of the electron when ultra violet radiation of frequency 1.6 * 1015/s strikes the surface of potassium metal .Threshold frequency of potassium is 5 * 1014 /s which principle is applicable and why? Solution) It is a problem of photoelectric effect (PEE) because of the phenomenon involved Kinetic energy of photo electron is where given by K.E = hf - hf0 Where, f = frequency of the incident photon and f0 = Threshhold frequency for PEE to take place. h = planck's constant. Thus, KE = h x (1.6 * 1015 - 5 * 1014 ) or, KE = h x 9 x 1014 or, KE = 6.626068 × 10-34 x 9 x 1014 J or, KE = 6.626068 × 10-34 x 9 x 1014 / (1.6 x 10-19) eV solve to get KE in eV.
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25 Mar 2007 23:24:12 IST
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but the result is for maximum kenetic energy
wat about the average kinetic energy
any idea please ?
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25 Mar 2007 23:25:53 IST
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thts wht i hve done(the same thing done by edison sir)!!!
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