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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jun 2008 12:00:06 IST
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Find the area of the closed planar figure formed by the intersection of x^2+y^2 = 1 and x+z=0.
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12 Jun 2008 21:54:02 IST
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That should be simple.
By solving the simultaneous equations for the two curves
x^2+y^2 = 1 and x+z=0.
Obtain the points of intersection say (x1,y1) and (x2,y2)
Now integrate the area between the first curve x-axis (also substitute values of y in terms of x) which gives Area A1
Then integrate the area between the second curve x-axis (also substitute values of y in terms of x) which gives Area A2
Finally area enclosed between the two curves = I A1-A2 I
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