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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jun 2008 12:07:22 IST
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a particle of mass m and charge q is thrown at a speed u in a uniform electric field E how much distance will it travel before coming to momentaly rest
ans===mu^2/2qE
(hc part 2 ques page 122 ques 47)
plzzzzzzzz ans
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9 Jun 2008 12:16:25 IST
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plzzzzzzz reply
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When a +ve charge q is thrown into an electric fieldE,It experiences a backward force F=qE/m due to which it stops after travelling some distance.
So,v=0,u=u,a=-qE/m and hence,
02-u2=-2(qE/m)S S=mu2/2qE.
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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