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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jun 2008 20:52:06 IST
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1 A point moves such that the sum of its distances from the four sides of a square of length ‘g’ is constant. Then what is the locus of the point??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jun 2008 20:53:32 IST
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it can only be the center of square..
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I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jun 2008 20:55:35 IST
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NO DUDE IT CAN ALSO BE THE VERTICES OF THE SQUARE ...AM WORKING ON THE PROB. WILL POST IT IN A MIN
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jun 2008 00:26:19 IST
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locus is points lying on and inside that square.
rate me if i m right.
correct me if i m wrong.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jun 2008 00:32:33 IST
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vikasbansal is correct and the sum of the distances will always be 2g (sum of length and breadth)
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---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jun 2008 17:27:47 IST
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Yes vikas is correct. For any point in or on the square the sum of distances will be 2g
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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