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ashishnavalakha (81)

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all math loving people here's some interesting puzzles to solve. do attempt it once.


1.) if hospital A delivers 200 babies while hospital B delivers 1000 then can u find out which hospital has greater chance of delivering precisely as many boys as girls assuming that probability of having boy or girl is same.


2.) prove this very simple question :    1


3.) prove this inequality without multiplying whole mess out :


4.) gossip puzzle : there are six gossip loving women. whenever one of them calls another by the end of conversation they both know everything that the other knew beforehand. one day each of the six women picks up a hot gossip which are different from each other. u have to find out minimum no. of phone calls required before all six of them know all six of the gossips.


enjoy solvig these. pls post ur answer with complete solutions.


NB : these puzzles are taken from some of the books and competions where i participated.


 


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oneyeartogo (217)

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Answer to question 2


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oneyeartogo (217)

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Is the answer to the 4th question 9 phone calls?


 


Answer to the First question


Is it the hospital with 200 babies.

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ashishnavalakha (81)

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ur 1st and 2nd question r right.but not 4th one.

"Always remember you're unique just like anyone else"-ALISON BOULTER

"Experience is what u get when u dont get what u want"-DAN STANFORD

" One robot can do what 50 ordinary men can but 100 robots can't do what an extraordinary man can "
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rudra.panda (2263)

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i think i have got the third one.

God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~

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shinee (234)

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edited


SHREYA
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oneyeartogo (217)

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Oh no I got 9 as the minimum. So either the answer is 9 or less than that (very unlikely)

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akshatamohanty (34)

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i got 7 calls for the last one.

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shinee (234)

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i have thought once again,and i got 8
this first woman calls the second, the third the fourth, the fifth the sixth. and the first woman calls the third, third the fifth so they both came to know everything. the first calls the sixth and these two too came to know everything, the fourth calls the fifth and later the second
Is the ans eight?

SHREYA
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oneyeartogo (217)

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@shinee


Please check once more urs is coming 9 calls (same way that I used)


1 1 1 1 1 1     (denotes each woman knows one gossip)


2 2 1 1 1 1   


2 2 2 2 1 1      (note: woman number 1 and number 3 have 2 different gossip each)


2 2 2 2 2 2


2 2 4 2 4 2


2 6 6 2 4 2


And 4 more calls


Total 9 calls

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shinee (234)

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no, it is coming out to be 8

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tarinbansal (3847)

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Q4 - The answer is 8.


The 6 numbers(1,2,3,4,5,6) denote 6 ladies and A,B,C,D,E,F are 6 diff. gossips.


The no. in red at the right hand side denote the No. of calls in a particular step. And U can see that after the third step, each lady knows all 6 gossips-ABCDEF.


1A   2B   3C   4D   5E   6F


Calls- 1+2, 3+4, 5+6 = 3 calls


=> 1AB   2AB   3CD   4CD   5EF   6EF


Calls- 1+3, 4+5 = 2 calls


=> 1ABCD   2AB   3ABCD   4CDEF   5CDEF   6EF


Calls- 1+6, 2+4, 3+5 = 3 calls


=> 1ABCDEF   2ABCDEF   3ABCDEF   4ABCDEF   5ABCDEF   6ABCDEF


So, total phone calls = 3 + 2 + 3 = 8.


 


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shashank_baveja (22)

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ans 4 the 4qus is 9 calls


let there b women  1      2      3       4     5      6


and they know gossip   a       b       c         d     e      f     rspcly


------call 1 ------1 -2


1 tells 2  abt a


2 tells 1abt b


so 1 knows  a b


2 knows ab


------call 2--------3-4


3 tells 4 abt c


4 tells 3 abt d


so3 knows  cd


4 knows cd


--------call3-------5-6


5 tells 6 abt e


6 tells 5 abt f


so  5 knows  ef


6 knows ef


----------------------------------


1 knows  abt a b


2 knows abt ab


3 knows  abt cd


4 knows abt cd


5 knows  abt ef


6 knows abt ef


------call4---1-4


1 tells 4 abt  a b


4 tells 1 abt cd


so 1 knows  a b cd


4 knows abcd


-------call5-2-5


2 tells 5 abt ab


5 tells 2 abt ef


so  2 knows ab ef


5 knows  abef


------call6-3-6-


3 tells 6 abt cd


6 tells 3 abt ef


so 3 knows  cdef


6 knows cdef


 


-------------------------------------------


1 knows  a b cd  (except ef)


2 knows ab ef  (except cd)


3 knows  cdef  (except ab)


4 knows abcd  (except ef)


5 knows  abef  (except cd)


6 knows cdef  (except ab)


-------call7- 1-3


1 tells 3  a b cd


3 tells 1  cdef


now


1 knows abcdef


3 knows abcdef


------call8 ---2-4


2 tells 4  abef


4 tells 2  abcd


now


2 knows abcdef


4 knows abcdef


-----call9-------5-6


5 tells 6  abef


6 tells 5  cdef


now


5 knows abcdef


6 knows abcdef


so all konw each gossip in 9 calls


 


 


 


 

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shashank_baveja (22)

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ans is 9 calls


first women calls


                                   2nd 3ed 4th


second women calls


                                  3ed 4th 5th


third women calls


                  &n