An ideal gas is taken from an initial state "i" to a final state "f" in such a way that the ratio pressure to the absolute temperature remains constant.What will be the work don by gas?
ok charles law says that for an ideal gas if the process happens at constant volume the ratio of pressure to absolute temp remains constant. so here the process mentioned in the problem is an isochoric or constant volume process and hence work done is 0 please correct me if i am wrong or nudge me if you hav any doubts
According to ideal gas equation PV=nRT Ratio of pressure to temperature is constant implies P/T = nR/V = constant implies Volume is constant, since R is universal constant and system is assumed close, so no change in number of moles.
Work done is defined as integral of P.dV where dV is small change in Volume.. So since dV is zero throughout, work done is zero
Moderation Team
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