| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 10:36:42 IST
|
|
|
a block of mass m andhaving a charge q is placed on a smooth horizontal table and is connected to a wall through an unstressed spring of spring constant k.A horizontal electric field E parallel to the spring is switched on.find the amplitude of the resulting SHM of the block----
ans:_ qE/k
|
|
|
|
20 Jun 2008 10:42:20 IST
|
|
|
ampltude will be reached when d case is of max displacement at given conditions ..........
in such a case
Eq=kx
x=Eq/k
|
nobody is wrong
even a stopped clock is right twice a day |
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Jun 2008 11:11:04 IST
|
|
|
Brother how can I paste my photo at my orkut account.
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Jun 2008 11:14:25 IST
|
|
|
i think ur ans is wrong
the right ans is 2qe/k.....
energy conservation
1/2kx2 = qex
|
yugank
|
this reply: 10 points
(with 2
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
DO YOU REALLY THINK THAT THIS IS THE CASE.
cmon people the equation Eq=Kx just gives us the condition for equilibrium condition. when initially the electric field force is more than the spring's backward pull it gains some velocity as there is some net acceleration acting at the equilibrium position it has a maximum velocity and it goes further due to that velocity it still has until it is stopped by the spring force. the point where the equilibrium is attained is actually the mean position of the SHM and the distance it goes further now from this mean position is the amplitude.
well this is the case when the electric field has not been switched off. and no where in the prob is it mentioned that the electric field is switched off
please correct me if i am wrong
|
FAILURE, THE FIRST STEP TO SUCCESS |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Jun 2008 11:28:22 IST
|
|
|
WELL I THINK @yugu901234 is correct
|
FAILURE, THE FIRST STEP TO SUCCESS |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Jun 2008 11:48:03 IST
|
|
|
so is the ans qe/k or the one told by yugu.........its actually a ques of HCV and i rember the ans being qe/k
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
