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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: if these two equation valids,then Prove that x^2/a^2+y^2/b^2=2
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matsci (0)

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paddy.dude (1156)

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iam getting the ans as x2/a2 + y2/b2=2sin2cos2       am i wrong


i squared both the equations and added them

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sriram.a (222)

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hey ur r right but dont u know additions
if u square and add u will get required equation yaar

<SRIRAM.A> on high way of IIT




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paddy.dude (1156)

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how come we get the ans



eq 1 on squaring

 


x2/a2cos2  +  y2/b2sin2 = 1


 


eq 2 on squaring we get


x2/a2sin2 +  y2/b2cos2  = 1


 


now if we add these two how can we get the required ans


it will come as


1/sin2cos2 (x2/a2 + y2/b2)=2


isnt it correct 


 

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sboosy (3065)

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\mbox{On squaring first equation} \ \frac{x^2\cos^2\theta}{a^2} + \frac{y^2\sin^2\theta}{b^2}+\frac{2xy\sin(\theta)\cos(\theta)}{ab} = 1 \\ \\ \mbox{On squaring second} \ \frac{x^2\sin^2\theta}{a^2} + \frac{y^2\cos^2\theta}{b^2}-\frac{2xy\sin(\theta)\cos(\theta)}{ab}=1 \\ \\ \mbox{Adding,we get} \ \frac{x^2}{a^2}+\frac{y^2}{b^2} = 2

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