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ADPDAVCTC (14)

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 Intensity ( E ) = d V/ d R


V = potential,  r = distance


E at a point inside a spherical shell is zero.


But  V at that point is minus (-) G M by (/)R


( M- mass ,R- radius of shell )


How ?????????????Pliz explain ...............................


 


 


adipic acid with silver oxide
    
v.sabarish (177)

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E, as you said is dV/dr...
dV refers to a small change in 'V'.... but the value of V remains constant....... -GM/R as you have said... and doesn't vary with the distance from the centre, r....
hence dV = 0...
therefore, E=0
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phystud (9)

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Another way of understanding this is that work is done only from bringing the particle from infinity to the surface of the sphere which gives the potential as -GM/R


Thereafter, no work is done as the field inside is zero. Hence, the potential is the same throughout inside the shell.

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