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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 09:42:41 IST
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CURRENT THROUGH CIRCUIT ' i ' IS 0.5 A .
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 09:49:41 IST
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for defining potential we need to take a refrence point......if we take Va=0 den Vo=-1V and Vb==0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 09:52:19 IST
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CURRENT FLOWS FROM HIGHER POTENTIAL TO LOWER POTENTIAL THEN HOW DOES IT FLOW FROM O TO B ??
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The copyright for the facts written above is held by x4
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 10:12:28 IST
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hey man b is at lowe potential than o..
if Va=0, then Vo=0 Vb=0 current flows through the resistor bbecause therre is a potential difference across it..so where is the problem?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 11:22:09 IST
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Use mesh analysis.
-2i + 1 + 1 - 2i + 1 - 2i = 0
3 = 6i
i = 0.5A
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 11:30:09 IST
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Its a pretty simple question. What's the problem in solving it? :O
All the 3 batteries are in series and all the 3 resistors are in series. So, net V = 3V Net R = 6 I=V/R =3/6 =0.5 A
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 19:29:09 IST
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in the circuit u have va = vb = vc then why does current flow ???what is potential at o ?????
if it is lower than that at a then why shud current flow from o to b as then b is at higher potential than o ?????????
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COPYRIGHT :
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 19:33:22 IST
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Yaar, see the circuit on a whole.
As a complete circuit, it doesnt have 3 batteries and 3 resistances. It effectively has a single battery of 3 V and a single resistor of 6 ohms. So there is a NET potential difference across a resistor. So the current flows.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 19:41:00 IST
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If u want to solve it analytically, I have shown this in figure.
Assume potentials at A = V, B = V', C = 0
Hence, P.D. across the resistor AB = (V+1) - V'
P.D. across the resistor BC = V' - (-1)
P.D. across the resistor AC = V - 1
Hence, there is some potential difference across each resistor. If U make an equation and solve it, u will get the same answer(although it wud be foolish to do so. This will convert a 2 line question into a full page length ques).
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 21:40:35 IST
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@x4 my prevous post is correct and it doesn"t refquire modification.. see potential at any point is subject to change according to the choice of reference point..
see for current to flow through a resistor a potentail difference is required across its two terminals ..which is available in this case..hence current flows through the resistor..
and finally o is at higher potential than b...
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Jul 2008 17:34:49 IST
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if Va=0, then Vo=1V Vb=0
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