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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Jun 2008 20:46:27 IST
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hcv - 2
page 167
Q-25 (b)
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1 Jul 2008 20:11:44 IST
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sm1 reply...me too having prob in it
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Know thyself
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2 Jul 2008 16:45:51 IST
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someone plzzz
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3 Jul 2008 08:36:11 IST
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draw the charge from any one battery
using mesh analysis
-q/2-q/4+24-12=0
3q/4=12
q=16c
Va-Vb=-q/2
=-16/2uf
=-8V answer
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3 Jul 2008 08:37:38 IST
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ya agree wid nishi.tiwari..
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I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME. |
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4 Jul 2008 15:42:21 IST
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what is mesh analysis???
i did'nt get how the third line was derived???
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we are the allies of konoha.....shinobis of the....sand
shubham sunder |
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4 Jul 2008 17:41:03 IST
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hey nishi,
can u pls explain???
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4 Jul 2008 20:24:19 IST
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sorry frnds i have actually used wrong word there
the equation i had wrritten is just by using krichoff's voltage law
sorry but if u want to know abt mesh analysis visit this
http://utwired.engr.utexas.edu/rgd1/lesson07.cfm
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4 Jul 2008 21:33:53 IST
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take the charge from batteryy then apllying krichoff law
then the equation is
-q/2-12-q/4+24=0
on solving this
we get
q ===16
then
v(a)-v(b) = -q/2
=-16/2
=-8v
if i m corect rate me
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5 Jul 2008 13:50:37 IST
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ans is -8 V jst use kirchoff's law
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. . . : : | | : : A T U L : : | | : : . . .
||~::~||THE ONLY THING YOU DON'T KNOW IS THAT WHICH YOU DON'T KNOW||~::~|| |
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5 Jul 2008 14:14:43 IST
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using KVL for the loop
we get 24- q/4- 12- q/2=0
q=16
again using KVL for a to b
now Va + 16/2 - Vb =0
Va-Vb = -8 V (ans)
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I WAS BORN INTELLIGENT!!!!!!!
EDUCATION RUINED ME
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