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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jul 2008 15:42:20 IST
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find the domian of the function:::
f (x) =
[ log 0.3 (x2 – 1) / x2 – 3x + 2 ]1/2
i m stuck while finding out the comon domian after drawing the number line...............
plz guys give me a detailed answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jul 2008 22:03:14 IST
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tell me if its right...i'll post a detailed answer!!!
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IIT is the ZENITH!!!
1 year 2 go for the ultimate exam of my lifetime!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jul 2008 22:17:38 IST
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x>2
My answer tellme if it is correct.
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that is what my answer means dear......x belongs to a set of values from 2 to infinity.....i.e x>2 is the right ans most probably....
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IIT is the ZENITH!!!
1 year 2 go for the ultimate exam of my lifetime!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jul 2008 08:28:53 IST
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i donno the answer yet ..................
but plzz give me a logical solution.............
hurry up guys its urgent..............
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jul 2008 08:46:14 IST
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[log{(x^2-1)/(x^2-3x+2)}]^1/2
(take base as 0.3..i not writing it)
so v have [log{ (x-1)(x+1)/(x-1)(x-2)}]^0.5
cancel x-1 in num n denom...note tht x cannot be 1..ie x-1 cannot be 0..
so v have x+1/x-2 inside the log
now the log has to return a positve value cuz then only u can apply the sq root to it
as base is <1 the num inside the log also has to be <1 so tht overall log value is +ve
so x+1/x-2<1 => 3/x-2 <0 => x<2 (but x not =1)
also x+1/x-2 >0(as inside log num shud be positive)
so from this u get x>2 or x<-1 but from 1st statement v got x<2
so answer is x<-1 or x belongs to (-infinity,-1)
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jul 2008 08:47:36 IST
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the mistake made in previous posts is tht they have failed to take into consideration tht the base(log base) is <1
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 01:40:18 IST
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Perfect answer computer001. Well done
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 16:58:08 IST
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cheers 
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 17:08:05 IST
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the input of log must be (o , 1) as it is under sqr root and base is <1 so
wats the right answer???
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