(x tan 2x - 2x tan x) / ((1-cos 2x)^2)

The answer is 1/2

Please give the step-by-step detail.

Thanks

                (x tan 2x - 2x tan x) / ((1-cos 2x)^2)

tan2x=2tanx/1-tan²x     ; 1-cos2x=2sin²x  ;       x/sinx =1

                2xtanx(1-1+tan²x)/1-tan²x  *4sin⁴x

    2x tan³x/(1-tan²x)*4sin⁴x=         (x/sinx)*1/2*1/(1-tan²x)=1/2