Let f denotes the force of friction . Then for the linear motion of th plank
F-f= M1a--------------(1)
and considering the motion of the sphere standing on the plank ( a non-inertial reference system ), because of no sliding , its angular accn= a1/R ( R = radius of the sphere ). where a1= accn of the centre of the sphere wrt the plank .Then introducing pseudo force we have : For angular motion of the sphere ::
fR = (2/5 M2 R^2) (a1/R) .........(2)
and for the linear motion of the sphere
M2a- f = M2a1 ........(3)
solving (1) and (2) and (3)I get the reqd accn .as
a=accn of the plank =F/( M1 + 2/7 M2)
and a1 = accn of the sphere wrt plank = 5/7 a ( directed opposite to the applied force )
Now accn of the sphere wrt ground = ( a-a1 ) = 2/7 a= 2/7 F/( M1 + 2/7 M2)