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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jul 2008 17:15:46 IST
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A charge of mass m is brought through a non uniform electric field. derive an expression fof velocity of the charge if the intensity of field increases by the expression y=2X+8and velocity by expression v=xy+78?
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6 Jul 2008 17:29:58 IST
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what do u mean by velocity changes???????? whats that expression..please be clear
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6 Jul 2008 21:00:06 IST
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I suppose that in the expression y = 2x + 8, y is the intensity of electric field i.e. y = E
Thus y = 2x + 8
also v = y.x+78 ...(1)
Now acceleration a = d2x/dt2 = dv/dt = dv/dx.dx/dt
or a = (y+x.dy/dx)(v)
or a = (y+x.dy/dx)(y.x+78)
since dy/dx = 2
Thus, a = (y+2x)(y.x+78)
To evaluate v=?
Now using F = ma
or Eq = ma
or y = ma/q
or y = m (y+2x)(y.x+78)/q
Now evaluate y using above equation and substitute in equation (1)
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