integrate sinx/x

its not integrable as the function is not continuous at x=0

i think if we expand sinx i.e. sinx expansion and divide it with x we may get the answer.

how do we know if the function is integrable or not?

it is based on continuity of a function.

plzz explain

rate assured

if a function is continous on its entire domain or a part of its domain then the function is derrivable or integrable on that particular domain.

ye kya

http://mathworld.wolfram.com/SineIntegral.html

Plz don't mislead .

roopa 1991 has given a completely wrong condition on integrability .It has nothing to do with continuity of the fn at a single point .

All of u have integrated ( defnite integral ) box fn . Now that's  discontinuous at every integral point ,yet the definite integral exists.

The qn is whether we can integrate it by using a closed form formula or not ( note Si(x) is not a closed form fn . )

And as this regards ,I can say that this indefinite integral can't be integrated in a closed form formula using elementary functions .

Yet definite integral of this fn in the range ( -inf to inf ) or (0 to inf ) has a closed form formula ( pi and pi/2 respectively ).

Plz don't mislead .

roopa 1991 has given a completely wrong condition on integrability .It has nothing to do with continuity of the fn at a single point .

All of u have integrated ( defnite integral ) box fn . Now that's  discontinuous at every integral point ,yet the definite integral exists.

The qn is whether we can integrate it by using a closed form formula or not ( note Si(x) is not a closed form fn . )

And in this regards ,I can say that this indefinite integral can't be integrated in a closed form formula using elementary functions .

Yet definite integral of this fn in the range ( -inf to inf ) or (0 to inf ) has a closed form formula ( pi and pi/2 respectively ).

thnxx