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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Find the value
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mathiit (0)

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If log 3=0.4771213


then find

    
sachinguptaiit (730)

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log(2.7)3 + (4/5)log(0.81) - (5/4)log(90)





 



3(log(27)-log(10)) + (4/5) (log(81)-log(100)) - (5/4)(log(9) + log(10))





 



 3(3log(3)-log(10)) + (4/5) (4log(3)-2log(10)) - (5/4)(2log(3) + log(10))





log(3)(9 +(16/5) -(5/2)) + log(10)(-3 -(8/5) - (5/4) )


Solve and put value of log3 as given and i think it is log10


log3(9.7) - 5.85


4.62807661-5.85


= -1.22192339


 


"Before you start some work, always ask yourself three questions - Why am I doing it, What the results might be and Will I be successful. Only when you think deeply and find satisfactory answers to these questions, go ahead."

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rudra.panda (2218)

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Here is my solution:


 


\log ((2.7)^3\times(0.81)^\frac{4}{5}\div(90)^\frac{5}{4})\\\\=3 \log \frac{27}{10}+\frac{4}{5}\log \frac{81}{100}-\frac{5}{4}\log 90\\\\=3(\log 3^3-1)+\frac{4}{5}(\log 3^4 -2)-\frac{5}{4}(\log 3^2+1)\\\\=\left(9+\frac{16}{5}-\frac{5}{2}\right)\log 3- \left(3+\frac{8}{5}+\frac{5}{4}\right)\\\\=\frac{97}{10}\log 3- \frac{117}{20}\\\\=4.6280766-5.85\\\\= -1.2219234


God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~


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sriram.a (210)

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Rudra dona u think 3rd last step its 9.7log3-5(117/20)

<SRIRAM.A> on high way of IIT




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rudra.panda (2218)

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Sorry typing error. Thanks for correcting it.

God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~


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