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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: indefinite integration---a good question------rates assured
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Xavier4 (4)

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Evaluate


    
ankurgupta91 (828)

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put x+sqrt(1+x^2) = t

[x+sqrt(1+x^2) ] / sqrt(1+x^2) dx = dt

dx/sqrt(1+x^2) = dt/ t

nw
integral t^15 dt /t
integral t^14dt
= t^15 /15

= [x+sqrt(1+x^2)]^15 / 15

thats the answer........

nobody is perfect......i m nobody..............
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allamraju (3422)

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Let us put  then we have



So the integral becomes

MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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deedee (1963)

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u can even use euler's substitution


put (x^2+1)^1/2=t +x ............then squarin u get .....


x^2+1=t^2+2tx+x^2 ...............


frm this u egt x =(1-t^2)/2t


substitute and solve u'lll surely get d asnwer .....


if nt .............do ask ................


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walk as if u dont care who rules d world

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