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man111 (47)

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(1) No. of integral point on the curves


x3+113=y3, lying in the first quarant.


ans=1,2,infinite,o

    
rajatsen91 (817)

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If these are the options the 2 is the answer as there are not infinite solutions and I have found two solutions .
x^3-y^3 = -11^3
now -11^3 can be broken into 2 integer factors in these ways
-121 *11,-1331*1
-11*121,1331*-1
now check each case, such as
let x-y = -11
x^2+xy+y^2 = 121
(0,11) and (-11,0) are two solutions

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Fermat's Last Theorem, in action


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Re:question

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