| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jul 2008 15:06:01 IST
|
|
|
ABCD is a square .F is the mid point of AB.BE is one third of BC .If the area of triangle FBE=108cm^2,then find the length of AC.
|
|
|
|
21 Jul 2008 21:19:54 IST
|
|
|
AB=BF/2=AF/2
BE=BC/3
ar(FBE)=1/2(BF)(BE)
108=1/2(AB/2)(BC/3)
(36)(36)=a^2
a=36
Therefore,AC=36(ROOT2)
|
BE HAPPY.
MAKE OTHERS HAPPY. |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
22 Jul 2008 21:04:31 IST
|
|
|
how is AB=BF/2=AF/2
AB/2=BF=AF
|
SHREYA |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
22 Jul 2008 21:08:00 IST
|
|
|
@shinee,in the question itself it is mentioned that F is midpoint of AB.So AB=BF/2=AF/2
and BF=AF=2AB
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
22 Jul 2008 23:21:12 IST
|
|
|
I think my answer is correct.Please check it and tell me if i am wrong.
|
BE HAPPY.
MAKE OTHERS HAPPY. |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
23 Jul 2008 12:29:47 IST
|
|
|
area of  =
 
|
God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~
 |
this reply: 5 points
(with 1
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
23 Jul 2008 21:13:43 IST
|
|
|
If F is the mid point of AB, then AB/2=BF=AF, AB=2BF=2AF
Ab should be twice of BF and AF
|
SHREYA |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
23 Jul 2008 21:26:09 IST
|
|
|
" If F is the mid point of AB, then AB/2=BF=AF, AB=2BF=2AF
Ab should be twice of BF and AF"
Yes what is the problem??
|
God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Jul 2008 20:46:05 IST
|
|
|
@rudra, once see wat krish1097 has written
|
SHREYA |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Jul 2008 23:37:03 IST
|
|
|
What do you want to say?????
AB/2=BF=AF, AB=2BF=2AF this is correct. What is the problem?
|
God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
![[Thumb - untitled.jpg]](/upload/2008/7/23/4b75bdb082a73116dc62e508bed654cb_47042.jpg_thumb)
