IIT JEE , AIEEE Forum - Mathematics , Vectors - distance of point of intersection..........

amulye

d distance of point of intersection of d lines of d lines

x-4/1=y+3/-4=z+1/7&

x-1/2=y+1/-3=z+10/8 frm (1,-4,7)

paddy.dude

let
x-4/1=y+3/-4=z+1/7 = a

and
x-1/2=y+1/-3=z+10/8 = b

so in the first case
x= a+4 , y = -4a - 3

in the second
x= 2b + 1 , y = -3b - 1

now at the pt of intersection the x and y coordintes must be equal
so
a+4=2b+1
ie a-2b=-3 ------------ 1

and
-4a - 3 = -3b - 1
ie -4a + 3b = 2 ------------- 2

solving these 2 equations u can get the value of a and b
put them in the respective equations to get the value of x , y and z which is the pt of intersection
then use distance formula and u will get ur ans

Ask & Discuss Questions with Community & Experts