A helathy youngman standing at a distance of 7m from a 11.8m high building sees a kid sliping from the top floor.With what speed should he run to catch the kid at the arms height(1.8m)

since the arms ht=1.8,effective ht at which child standing is=11.8-1.8=10

time taken tofall by the child is h=0.5*g*t2

hence t=1.414sec.during this time man has to cover adistance of 7m so that he can save

velocity at which he should run is v=d/t=7/1.414=4.95m/sec

rate me if useful