NO

yes,it is repeated after a period of 2

rate me if it is helpful

YES BROS.......BUT THE PERIOD IS 1 NOT 2PI

No it is NOT periodic.

@shanaditya..........

if the period was 1 then f(x) would've been equal to f(x+1) for ALL x ....i.e. sin[x] = sin[x+1]

But this fails at at least one point  x=1/2.

At x=1/2,we get

       sin[0.5] = sin [1.5]

sin0 = sin1

0 = sin1.........which is absurd.

but nitish 971 , it is periodic after 2

it means if f[x]=sinx   therefore f[x+2]=sin[x+2]

therefore

f[x]=f[x+2]  which is always true in case of sinx

NO SIN MOD X IS NON PERIODIC FUNCTION BETWEEN  pi/2 TO -pi/2OUT OF THIS LIMIT IT IS PRIODIC WITH PERIOD WITH 2 pi

@coolguy_2008

The function is f(x)= sin[x] where [.] denotes the greatest integer function!

It is NOT  sinx.

f(x)=f(x+2) is true for sinx but not for sin[x].

For sin[x],

at x=0,

f(x)= sin[0] = 0.

f(x+2)= sin[0+2] = sin[6.28] = sin6 which is not equal to 0!!

yes it is periodic with period 1/2. as the period of [x] is 1 and period of sinx is  .

NO IT ISNT!!

Read the earlier posts.