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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: optics
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anchitsaini (4377)

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optics


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anchitsaini (4377)

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click on image to see the qn completely

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astatine19 (1404)

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It is clear that the relative velocity will only be perpendicular to the axis


1 / v + 1 / u = 1 / f


so,


v = uf / u+f


I = O v / u


I = (0.5 cm) f / (f + u)


dI/dt = -(0.5cm) f / (f + u)^2 * du/dt


Putting f = 40 cm and u = -30 cm, du/dt = 4cm/s,


|dI/dt| = 0.8 cm/s = v


This is the speed with which one image will approach the principal axis. However, since we want relative velocity, we need the double of v which is 1.6 cm/s


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anchitsaini (4377)

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i took u =+ 30 , damn damn

anyways thanks

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