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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Aug 2008 19:33:03 IST
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A question done in my class
x^2 - 2(a^2 + b^2 + c^2)x +3L(ab +bc +ca) =0
where a,b,c represent sides of a triangle, then find the condition on L for the equation to have real roots.
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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23 Aug 2008 19:53:39 IST
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wait posting the solution.
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I like to be myself. |
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23 Aug 2008 20:54:28 IST
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@ rajat
You haven't taken x in the second term of the given quadratic equation.
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"The journey of a thousand miles begins with one step."
- Lao Tzu
Like and unlike the proverb above, the solution to a problem begins (and continues, and ends) with simple, logical steps. But as long as one steps in a firm, clear direction, with long strides and sharp vision, one would need far, far less than the million of steps needed to journey a thousand miles. And mathematics, being abstract, has no physical constraints; one can always restart from a scratch, try new avenues of attack, or backtrack at an instant's notice. One does not always have these luxuries in other forms of problem-solving (e.g. trying to go home if you are lost). |
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23 Aug 2008 21:21:41 IST
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Where is the x in 2(a^2 + b^2 + c^2)?
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24 Aug 2008 02:12:06 IST
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Err, I missed the x but I edited my post after 30 seconds or so. Seems you didnt see the correction.
Also the answer is numeric only.
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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25 Aug 2008 20:22:14 IST
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Seems no one is interested in doing good level IIT problems but all are up for out of course olympiad probs.
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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