IIT JEE , AIEEE Forum - Physics , Mechanics - pls ans this question on kinematics, rates for sure........... very simple.......

krithika.r

When a body is projected vertically up from the ground, its velocity is reduced to 1/4^th of its velocity at ground. Then the maximum height reached by the body is_____?

please give me a answer with detalied solution. rates for sure

gauravtargetsiit

at what instant is the velocity reduced to 1/4th of initial velocity??????

DattSAi

Formula:

Velocity of the body at the foot

Because a = -g

ignore me if any mistakes are present

rate me if useful

nishant_88

v^2-u^2=2ah

v=u/4
a=-g
u^2(1/16 - 1)=-2*10*h
h=3/64 u^2

gauravtargetsiit

bhai at maximum height the velocity is zero as the stone is thrown vertically upwards....you people are taking it u/4.......

gs3extreme

v^2 = u^2 - 2gh (acc. negative becoz in opposite direction to velocity)

u^2/16 - u^2 = -2gh

-15u^2/16 = -2gh

hence h = 3u^2/64

Protyush_Sahu

v^2 - u^2 = -2gh

u^2/16 - u^2 =-2gh

-15u^2/16 =-2gh

h = 3u^2/64

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