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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: pls ans this simple question based on dynamics.......rates for sure.......
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krithika.r (20)

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a ball with mass 500g hits the wall with velociyt equal to 10m/s such that it makes an angle 60o with the normal. it bounces back with the same speed making an angle of 60o with the normal. Determine the change in momentum.


 


please give me a answer with detalied solution. rates for sure


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gauravtargetsiit (240)

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5kg m/s

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krithika.r (20)

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ans with steps please


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 


 

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DattSAi (19)

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formula



2 x 0.5 x 10 x cos60 = "


2x5x1/2= 5 Kg m/s



 


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DattSAi (19)

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formula



2 x 0.5 x 10 x cos60 = "


2x5x1/2= 5 Kg m/s



 


rate me if it is useful...

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varun.tinkle (1370)

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SIMPLE SUM DUDE
CHANGE IN MOMENTUM=2MVCOS@ (SINCE VELCOITY PARALLEL TO THE NORMAL IS IN THE SAME DIRECTION)
=5

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