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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Apr 2007 11:15:54 IST
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If f(x)=x2+3x-40/x2+5x-14, x  -7, x 2 then find the least and greatest integral values of x for which f(x)<0 Please explain
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The left image is Bihar in 2020 |
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7 Apr 2007 14:18:10 IST
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y = (x2+3x-40)/(x2+5x-14)
y = {(x-5)(x+8)}/{(x+7)(x-2)}
y < 0 when x  (-8,-7)  (2,5)
Hence the least integral value of x for which y < 0 is 3.
Hence the greatest integral value of x for which y < 0 is 4.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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