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Ask iit jee aieee pet cbse icse state board experts Expert Question: indefinite integration
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[Post New]7 Apr 2007 11:31:16 IST
    Subject: indefinite integration
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vinithreddyr (0)

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[ ][ ] 1+x+[ ]x+x*x/[ ]x+[ ]1+x
    
[Post New]7 Apr 2007 21:13:13 IST
    Subject: Re:indefinite integration
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iitkgp_bipin (6144)

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I think the question is :

I = {1+x+ (x+x2)}/{(x+1) + x} dx

Now rationalize it :

[{1+x+ (x+x2)}/{(x+1) + x}].[{(x+1) - x}/{(x+1) - x}]

= (1+x)1/2 - x1/2 + x(1+x)1/2 - x3/2 + x1/2 + x3/2 - x(1+x)1/2

= (1+x)1/2

Hence I = (1+x)1/2 dx = (2/3)(1+x)3/2 + c
 
Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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