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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Aug 2008 11:07:13 IST
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If f(x) defined by f(x)=
1,x=0
-1,x=1
then f(x) is continous for all x except x=0,1.how???????????
Please tell me what shud be our stategy to solve when we see mod values
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Aug 2008 12:10:29 IST
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Because x^2 - x = x (x - 1) so critical points are 0 and 1.
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- Gaurav Ragtah (spideyunlimited)
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Re:Continuity and differentiation (rates assured)
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I like to be myself. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Aug 2008 18:04:04 IST
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but hw did u gt d left hand limit for x=0 as -1 b'cauz f(x)=-1 is satisfied for values (-infinity,0) and (1,infinity) as well, means values greater than 0 also.
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there are two rules to succeed
1.never tell everything you know.
2.never tell you know everything.
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