2 SO₂ + O₂   ( greater than or equal to) 2 SO₃ (g)

PLEASE SAY THE RATE LAW FOR IT.

R=K [ SO₂ ]² [ O₂ ] If it is experimentally found out

DON'T MIND THAT INEQUALITY SIGN............ JUST GIVE THE RATE LAW

R=K [ SO₂ ]² [ O₂ ]

RATE LAW= THE EQUATION THAT DESCRIBES MATHEMATICALLY THE DEPENDENCE OF THE RATE OF A REACTION ON THE CONCENTRATION TERMS  OF THE REACTANTS IS KNOWN AS YHE RATE EQUATION OR RATE LAW

EX:

1)   2A ----------> PRODUCTS

          RATE LAW=

2) A+B+C------> PRODUCTS

         RATE LAW==

HOPE U R CLEAR ABT THIS CONCEPT

the rate law for this eqn cannot be predicted without experimeantation

it can be given as R = K [SO2]^a[O2]^b

here a & b may or may not be equal to 2 & 1 respectively....

the values of a & b are equal to the stoichiometric coefficients only if it is given that the reaction follows the LAW OF MASS ACTION

ya rate law can be predicted by experiments or if u know the mexhanism of the reaction as in "rate determining step"(RDS)..........

Rate law is only predicted experimentally.

It says that the rate of reaction is directly proportional to the conc. of products where k is a constant

In this case

R=k[SO2]^x[O]^y

where d value of x and y is uncertain

RATE IF USEFUL