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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Apr 2007 16:04:43 IST
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What is the inradius of the triangle with sides 3,4,5?
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Nikhila
Only those who dare to fail greatly can ever achieve greatly. |
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7 Apr 2007 16:07:17 IST
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plzzzzzzzzzz
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Nikhila
Only those who dare to fail greatly can ever achieve greatly. |
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7 Apr 2007 16:10:41 IST
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the ans is....2
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7 Apr 2007 16:12:21 IST
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rite or wrong....tell me then i can give the soln
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7 Apr 2007 16:22:43 IST
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Hey Nikhila and Ankeet, This's simple yaar.... For any triangle, " AREA = Inradius*( Perimeter of triangle ) / 2 " So : here, Area = 1/2*3*4 = 6 ie, inradius = 2*area / perimeter = 12 / (3 + 4 + 5) = 1 Please let me know if there are any mistakes....
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7 Apr 2007 16:26:54 IST
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Ans is 2
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Nikhila
Only those who dare to fail greatly can ever achieve greatly. |
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7 Apr 2007 16:26:59 IST
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inradius = (area of triangle)/s where s = (a + b+ c)/2 therefore inradius = 6/6 = 1 In my opinion the inradius has to be 1 maybe the experts would rectify the ans.
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"Imagination is more important than knowledge."
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7 Apr 2007 16:27:52 IST
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yeah.....its rite....just a silly mistake for me....
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7 Apr 2007 16:29:24 IST
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its gotta be 1......see once more time nikhila....or else the ans given in ur source is wrong......
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7 Apr 2007 16:32:13 IST
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its a quesion from FIITJEE tst series. its ok
answer might be wrong
thanks aneeket , priyesh and avinash
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Nikhila
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7 Apr 2007 16:43:48 IST
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Even mistakes make mistakes...don't they??!!!
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7 Apr 2007 19:56:38 IST
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r = (area)/(semi-perimeter)
area = (1/2)(3)(4) = 6
semi-perimeter = (3+4+5)/2 = 6
Hence r = 6/6 = 1
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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