IIT JEE , AIEEE Forum - Physics , Mechanics

rohitj

a mass of 2.9 kg suspended from a string of length 50cm isat rest anotherbody of mass 100g which is moving witha velocity 150 m/s horizontally strikes and sticks to it

1. what is the tension in the string when it makes an angle of with the vertical?

2.will it complete a vertical circle?

ans:1-135.3

2-yes

ABHI_23

well the vel of part... =150

momentum = 150*0.1=15 = 3* x

so x = 5

tension at 60 deg = m( gcos60 + x^2/r)

=3(10*0.5 + 25/0.5)

=165N

so i think ans is 165 and yes resp

varun.tinkle

SEE ABHI UR TOTALLY WRONG
THE WORKING IS THIS
THE SYSTEM WILL LOOSE V DUE TO GAIN IN POTENTIAL ENRGY
SO THE NEW VELCOITY
=
1.2MV2^2=1/2MV^2-MGL(1-SIN@)
SOLVING WE GET V2^2=20
THE REAL EQUATION IS
T-MGCOS@=MV^2/R
T=M(GCOS@+V^2/R)
SOLVING WE GET T AS 135 NEWTON

2ND PART OF THE EQUATION
FOR COMPLETING THE CIRCLE
AT THE HIGHEST POINT
T+MG=MV^2/R
T CAN TAJE ANY VALUES SO FOR SURETY
MG=MV^2/R
SOLVING IT WE GET V^2S 5
SO THE VELOCITY AT THE HIGHEST POINT =5
SO WE HV TO VERIFY IT BY THE WOK AND ENERGY METHOD
1/2MV^2=1.2MV1^2-2MGL
V^2=5
SO IT WILL COMPLETE THE CIRCEL
!PLS RATE ME IF U FIND ME USEFUL
!!!CHEERS!!!

ABHI_23

YA you are right in first part of ques !!!!

but i have shortcut for 2 part

if the particle has to complete one circle then vel at initial posn =

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