Sums on Gravitation

 

1.Two masses m1 & m2 revolve round a common center of mass,forming a binary system.Show that the common time-period T is given by,T=2 ,where r is the distance of 2 ,masses.

2.The acceleration due to gravity at 2 places are g1 & g2.From the same height at 2 places if a body be dropped, it takes t less to reach the ground in the second place than the first, but the velocity on reaching the ground in the second place is greater by v than in the first place.Prove that g1g2=v^2/t^2.

Please solve.Rates assured......................

Please solve some one.

in the first question,is 'a' the gravitation constant G. 

WELL I CAN TRY IT

The masses are m1   &   m2 

so first we can find centre of mass 

COM = at m2r/m1+m2  (from  m1)

and at m1r /m1+m2  (from m2)

so    for m1 centripital force =gravitional force

         so           =  

   so

 so         SO  a =G/r^2 

 PLZ RATE  IF  FOUND  CORRECT

can  anybody plz tell me that is my answer correct or not!!!!!!!!!!