IIT JEE , AIEEE Forum - Physics , Electricity - potential due to thin uniformly charged spherical shell

mukesh

prove that potential due to thin uniformly charged spherical shell at an external point is same as that of an equal point charge at centre

iitkgp_bipin

Use a concentric Gaussian sphere of radius r outside the shell.

E.dA = Q_in/

₀

E(4

r²) = Q/

₀

E = (1/4

₀)(Q/r²)

V = _infinity

^r (-Edr) = _infinity

^r (-1/4

₀)(Q/r²).dr

V = (1/4

₀)(Q/r)

sanat_sachar

as we consider the the guassian surface passing through that point and the potential in guassian surface0 donot depend upon radius of surface so the both potential should be same

khinart

Hey there is a much quite easy way to understand here.We know that electric field due to a point charge is zero at every point inside the surface.And we also know that the electric field due to a point charge is KQ/R(square).And I think that U also must be knowing that E=-dV/dr.
since the electric field is 0 so the potential is comstant.

khinart

Hey there is a much quite easy way to understand here.We know that electric field due to a point charge is zero at every point inside the surface.And we also know that the electric field due to a point charge is KQ/R(square).And I think that U also must be knowing that E=-dV/dr.
since the electric field is 0 so the potential is constant.

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