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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Sep 2008 15:02:02 IST
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please solve this differentiation
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5 Sep 2008 15:09:04 IST
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5 Sep 2008 15:15:52 IST
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dy/dx = 6(ax^2 + bx +c)^5(2ax +b)
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6 Sep 2008 23:23:44 IST
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Use the chain Rule...
d/dx(ax2+bx+c) = d/d(ax2+bx+c) {ax2+bx+c)6 X d/dx(ax2+bx+c) = 6(ax2+bx+c)5 X {2ax + b). d/dx(c) = 0, since c is a constant ...That's the answer...Rate if necessary...
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