E - iR -  L(di/dt) = 0

in dis case, we use inductor vich will oppose increase in emf. simply take d example, whn we switch on an ac circuit ( in household circuits),,, emf increases wid increases in time. but whn we use inductor in d circuit, self inductance is produced in it vich will try to oppose d effect of increase in emf  i.e.  in sinusoidal graph of emf , it will always remain const. there4 current is also const.

     as u r askin y I is const. though it is given as 5 A/s i.e. it changes, then i wud like to tell u dat, d increase in emf will try to increase d current at const rate,,,,but as self inductance produced in d inductor, it will prevent d effect of increase in current( or emf),,,, so we get always a const. current.

     if i m correct rate me,,,,,,otherwse tell me...........

 i dont really think u have answered correctly since the di/dt which is given includes the effect of the inductor and so does the final current which flows through it....

and even if u are correct and constant current flows due to  the inductor what is the need to derieve a complex expression like

we could directly say the current is constant and would remain constant and is independent of the time....

 so nobdies got guts to answer

cn u plz put d ans in expanded form.........help us in knowing d ans.......