the 10thcommon term between  the series 3+7+11+............,and 1+6+11+.........is

a)191

b)193

c)211

d)none of these

plz answer with explanation

for d firstsequnce tnth term luks like (4n-1) for d second one tnth term luks like(5n-4)

thus tehy both shdu b equal for common term u get n as 3

then if u luk carefully then d terms havin 1 in d unitz place r d common terms bt leavin one like

11 is d firsat common term then itz 31 then itz 51 then it wud b 71 then 91 ...and so on .......

u get d answer as a)

here

S₁ = 1 + 6+11+16+21+26+31+36+41+46+51+.............n terms

S₂= 3 + 7+11+15+19+23+27+31+35+39+43+47+51..........n terms

  Let  S be the series of the common terms

S = 11+ 31 + 51+...........+ a₁₀

You can see the Common diff is 20

Therefore  a₁₀ = a+9d = 11+9(20)=11+180 = 191