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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Sep 2008 18:59:00 IST
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ncert----pg-98 gives value of drift speed as 
whereas h c verma---pg 173 gives value of drift speed as 
where t = avg time b/w 2 successive collisions
E = electric fd intensity
e = charge on electron
m= mass of one electron
which one is correct????
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laziness pays now.....
hard work L8ter....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 11:37:54 IST
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nd da worst part iz dat both de books hav given their respcetive proofs ! !
plzz help...........
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what is this life so full of care ?
we have no time 2 stand & stare !!!!
--DAVIES--
laziness pays now.....
hard work L8ter....
but both pays ! !
If u can fill the unforgiving minute with sixty seconds worth of distance run;urs is da world n all dats in it----------->>>>a Russian who spend 7 yrs in siberia said dat the above lines helped sustain him
p.s. u wont loose ur rates if u will RATE me-------------->>>>>>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 19:32:54 IST
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v've been told dat d 1st one is correct n its explanation has been given in resnick halliday krane...
if u want d expln then temme......i'll post it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 00:44:09 IST
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In HcV, The final thing is that Vd = k E where E is the electric field and k is a constant.
Vd = a t = eEt / m is derived as follows :
Let t1 , t2 , ... tn be avearge time intervals between 2 consecutive collisions suffered by a free electron. Velocities acquired by various electrons, moving with an accln a are :
v1 = u1 + at1
v2 = u2 + at2
v2 = u2 + at2
..................
vn = un + atn
Hence average velocity Vd with which an electron drifts under the electric field is given by :
Vd = ( v1 + v2 ..................vn ) / n
= [ ( u1 + at1 ) + ( u2 + at2 ) + .......( un + atn ) ] / n
= [ ( u1 + u2 + ....... un ) / n ] + a ( t1 + t2 + ....... + tn ) / n
= 0 + at
[ ( u1 + u2 + ....... un ) / n ] = 0 comes frm the fact that the velocities r random in the beginning i,e, there is no net velocity of electron in one direction.
where, t is the average time interval between 2 consecutive collisions
= ( t1 + t2 + ....... + tn ) / n
so, Vd = at = eEt / m
then the constant Vd = k1 E
so ultimately there is just a small difference of constant .
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 09:16:41 IST
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hc verma gives.......
s = 1/2 a t *t ( u = 0 ; as already given above by ramyani.......)
s= dist bw 2 collisons
a = acc= eE/m
t= avg time b/w collisons
s = 1/2 (eE/m)t*t
Vd= s/t
Vd= 1/2 (eE/m)t
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what is this life so full of care ?
we have no time 2 stand & stare !!!!
--DAVIES--
laziness pays now.....
hard work L8ter....
but both pays ! !
If u can fill the unforgiving minute with sixty seconds worth of distance run;urs is da world n all dats in it----------->>>>a Russian who spend 7 yrs in siberia said dat the above lines helped sustain him
p.s. u wont loose ur rates if u will RATE me-------------->>>>>>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 09:17:50 IST
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nd iz it rite 2 ques de credibility of such a reputed book as hc verma ????????????
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what is this life so full of care ?
we have no time 2 stand & stare !!!!
--DAVIES--
laziness pays now.....
hard work L8ter....
but both pays ! !
If u can fill the unforgiving minute with sixty seconds worth of distance run;urs is da world n all dats in it----------->>>>a Russian who spend 7 yrs in siberia said dat the above lines helped sustain him
p.s. u wont loose ur rates if u will RATE me-------------->>>>>>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 09:25:59 IST
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@ ramyani...........
cant v put it diz way..........
Vd = avg drift speed.........
= (inital speed + final speed) /2
= (0 +eEt / m) /2
=1/2 (eE/m)t
= wot mr h c verma thinks....
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what is this life so full of care ?
we have no time 2 stand & stare !!!!
--DAVIES--
laziness pays now.....
hard work L8ter....
but both pays ! !
If u can fill the unforgiving minute with sixty seconds worth of distance run;urs is da world n all dats in it----------->>>>a Russian who spend 7 yrs in siberia said dat the above lines helped sustain him
p.s. u wont loose ur rates if u will RATE me-------------->>>>>>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 10:14:14 IST
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puja is right.. my teacher has been a student of hc verma and he told that the difference is that hc verma has given the explanation on the base of drift velocity theory where the average drift velocity is important!! so both books are correct as the drift velocities they hav calculated are different!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 16:38:36 IST
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@ islahul_101
"both books are correct as the drift velocities they hav calculated are different!! "
ddn relly got diz....................
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what is this life so full of care ?
we have no time 2 stand & stare !!!!
--DAVIES--
laziness pays now.....
hard work L8ter....
but both pays ! !
If u can fill the unforgiving minute with sixty seconds worth of distance run;urs is da world n all dats in it----------->>>>a Russian who spend 7 yrs in siberia said dat the above lines helped sustain him
p.s. u wont loose ur rates if u will RATE me-------------->>>>>>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 20:27:12 IST
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in the proof given by u here that is
s = 1/2 a t *t ( u = 0 ; as already given above by ramyani.......)
s= dist bw 2 collisons a = acc= eE/m t= avg time b/w collisons s = 1/2 (eE/m)t*t Vd= s/t Vd= 1/2 (eE/m)t
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 20:29:33 IST
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in the proof given by u here that is
s = 1/2 a t *t ( u = 0 ; as already given above by ramyani.......)
s= dist bw 2 collisons a = acc= eE/m t= avg time b/w collisons s = 1/2 (eE/m)t*t Vd= s/t Vd= 1/2 (eE/m)t
how is v=s/t this formula can be used only if accleration is 0 i mean the full formula is s=ut+1/2at^2 s=1/2at^2 u=0 = 1/2*eE/m*t^2
v^2=u^2+2as u=0 and a=Ee/m s =1/2*eE/m*t^2
solving we get again v=eE/m i think ncert is right
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 20:38:21 IST
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@ ganesha
bingo......
i think mr hc verma dinks differently here
ncert must b correct.....
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what is this life so full of care ?
we have no time 2 stand & stare !!!!
--DAVIES--
laziness pays now.....
hard work L8ter....
but both pays ! !
If u can fill the unforgiving minute with sixty seconds worth of distance run;urs is da world n all dats in it----------->>>>a Russian who spend 7 yrs in siberia said dat the above lines helped sustain him
p.s. u wont loose ur rates if u will RATE me-------------->>>>>>
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