Question no 35
M1g-T =m1a?????.(1)
T1-M3g=m3a?????(2)
-m3gsin30T-T1=m2a?....(3)
Adding .(1) (2) (3)
M1g-m2gsin30-m3g=(m1+m2+m3)a
a=(m1g-m2gsin30-m3g)/m1+m2+m3
substituting m1=500,m2=100,m3=50,
a=400g/650
a=8g/13
please tell me whether i am right
please rate me for my hardwork