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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:43:33 IST
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imagine that i have a circle(radius R) wit a smaller circle inside.when i put the circle(radius r and both have same cantre) in a horizontal plane and let the big circle rotate 1 revolution.
question:
1)as we know the displacement of the big circle is 2*pi*R,wat im intrested is the smaller circle,can anyone describe the smaller circle's motion?
2)wat im confuse is why the smaller circlea(which also complete 2 revolution)have the same horizontal displacement as the big circle.anyone can ans my question?
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i wan go iit as a exchange student next year(2009) |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:45:05 IST
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HORIZONTAL DISPn IS SAME FOR CENTRE OF CIRCLES
SO IT IS SAME AS THAT OF BIGGER ONE
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:46:31 IST
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hey abhi the friction will be an internal force for the system if we consider both the circles as the system
danny i think the dispacement of the centre of mass will be 2*pi*R bcoz ofthe larger circle but as the smaller circle has the same centre it will also coiver a distance of 2*pi*R
do rate if useful
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:47:01 IST
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nope,as i just intrested about wat happen to the small circle as the big circle rotate,coz im confuse
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:49:50 IST
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I THINK if surface have friction then it will rotate with the larger circle
and have same displacement
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:51:29 IST
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as the bigger circle rotates the smaller circle doesn`t rotate if
friction = 0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:53:07 IST
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hey abhi y r u considering friction as it is the internal force of the system
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:56:45 IST
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i need to know as the big circle make 1 rev,the small circle also make 1 rev,why their horizontal displacement will be the same
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 21:59:01 IST
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if there is no friction then the bigger circle will slip below the smzller circle
and the smaller circle will not rotate
plz rate if found correct
BEST OF LUCK
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 22:03:13 IST
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the horizontal dispacement of both the circles is same as the bigger circle, as the horizontal displacement is given by the displacement of centre of mass and centre of mass of the system containg both the circles is equal to 2*pi*R. got it or nt dude
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 22:04:11 IST
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any other answer,sry to say ABHI_23 doesnt clear my confusion
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 22:04:11 IST
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hey abhi how can there be friction if both the cicles dont touch only plz explain
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 22:12:54 IST
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plz let me know if this figure correctly picturises ur problem...............

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A Poet does With A Pen
A Guitarist With A Guitar!!!! DReam On!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 22:14:40 IST
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yes i also thought of the same figure
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Sep 2008 22:18:17 IST
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SORRY I INTERPRETED THE QUES WRONGLY!!!!!!!
IF THEY ARE BOTH MOVING WITH SAME ANGULAR VELOCITY AND HAVE SAME
CENTER THEN BY CONSERVATION OF ENERGY ANDMOMENTUM
ITS HORIZONTAL DISTANCE WILL BE SAME
HOPE NOW CONFUSION IS CLEAR !!!!!!
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