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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Sep 2008 17:19:47 IST
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a shepherd buys 9 goats at the end of 1998. henceforth onwards every year he adds p% of goats at the beginning of that year and sales q% of the goats at the end of the year where p>0 and q>0.if at the end of year 2002 , after making the sales, he is left with 9 goats, then
a)p=q b)p<q c)p>q d)p=q/2
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"Only two things are infinite, the universe and human stupidity, and I'm not sure about the former." --Albert Einstein |
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16 Sep 2008 17:44:11 IST
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p>q
This is because when u sell, u sell q% of (p+100)% of initial t 100% of initial goats. And when initial and final values r equal, it simply implies that p must be greater than q.
Take for example, 10% addition on 100Rs gives 110Rs, while 10% deduction of that 110 Rs gives only 99 Rs, which is less than 100. If some1 wants, i can give the simple mathematical proof too.
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16 Sep 2008 17:50:07 IST
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thnx
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"Only two things are infinite, the universe and human stupidity, and I'm not sure about the former." --Albert Einstein |
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